I want to print out i
in my iteration on Jupyter notebook and flush it out. After the next iteration, I'll print the next i
. I tried solutions from this question and this question, however, it just print out 0123...9
without flushing the output for me. Here is my working code:
import sys
import time
for i in range(10):
sys.stdout.write(str(i)) # or print(i, flush=True) ?
time.sleep(0.5)
sys.stdout.flush()
these are my setup: ipython 5.1, python 3.6. Maybe, I missed something in the previous solution?
When you have Jupyter notebook opened, you can do this by selecting the Cell -> All Output -> Clear menu item.
To clear output in the Notebook you can use the clear_output() function. If you are clearing the output every frame of an animation, calling clear_output() will create noticeable flickering. You can use clear_output(wait=True) to add the clear_output call to a queue.
To show the full data without any hiding, you can use pd. set_option('display. max_rows', 500) and pd.
#Try this:
import sys
import time
for i in range (10):
sys.stdout.write('\r'+str(i))
time.sleep(0.5)
The first answer is correct but you don't need sys
package. You can use the end
parameter of the print
function. It specifies what to print at the end, and its default value is \n
(newline) (docs1, docs2). Use \r
(carriage return) instead.
import time
for i in range (10):
print(i, end="\r")
time.sleep(0.5) # This line is to see if it's working or not
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