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Is there an easy way with Python f-strings to fix the number of digits after the decimal point? (Specifically f-strings, not other string formatting options like .format or %)
For example, let's say I want to display 2 digits after the decimal place.
How do I do that? Let's say that
a = 10.1234
553
The f-string was introduced(PEP 498). In short, it is a way to format your string that is more readable and fast. Example: The f or F in front of strings tells Python to look at the values inside {} and substitute them with the values of the variables if exist.
How to Format a Number as Percentage. Python f-strings have a very convenient way of formatting percentage. The rules are similar to float formatting, except that you append a % instead of f . It multiplies the number by 100 displaying it in a fixed format, followed by a percent sign.
As of Python 3.6, f-strings are a great new way to format strings. Not only are they more readable, more concise, and less prone to error than other ways of formatting, but they are also faster!
In Python source code, an f-string is a literal string, prefixed with 'f', which contains expressions inside braces. The expressions are replaced with their values.
Include the type specifier in your format expression:
>>> a = 10.1234
>>> f'{a:.2f}'
'10.12'
When it comes to float numbers, you can use format specifiers:
f'{value:{width}.{precision}}'
where:
value is any expression that evaluates to a numberwidth specifies the number of characters used in total to display, but if value needs more space than the width specifies then the additional space is used. precision indicates the number of characters used after the decimal pointWhat you are missing is the type specifier for your decimal value. In this link, you an find the available presentation types for floating point and decimal.
Here you have some examples, using the f (Fixed point) presentation type:
# notice that it adds spaces to reach the number of characters specified by width
In [1]: f'{1 + 3 * 1.5:10.3f}'
Out[1]: ' 5.500'
# notice that it uses more characters than the ones specified in width
In [2]: f'{3000 + 3 ** (1 / 2):2.1f}'
Out[2]: '3001.7'
In [3]: f'{1.2345 + 4 ** (1 / 2):9.6f}'
Out[3]: ' 3.234500'
# omitting width but providing precision will use the required characters to display the number with the the specified decimal places
In [4]: f'{1.2345 + 3 * 2:.3f}'
Out[4]: '7.234'
# not specifying the format will display the number with as many digits as Python calculates
In [5]: f'{1.2345 + 3 * 0.5}'
Out[5]: '2.7344999999999997'
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