First element of an array with condition

Question

Is there a shorter way to find the first element in an array meeting some conditions than this:

my_array[ my_array.index {|x| x.some_test} ] 

Answer 1

Try this:

my_array.find{|x| x.some_test } 

Or here's a shortcut (thanks @LarsHaugseth for reminding about it)

my_array.find(&:some_test) 

Answer 2

As for me find sounds confusing. As i am expecting receive more than one object for such a request.

I prefer to use detect for getting distinct one.

And select for finding all of them.

Here what ruby docs tells about them:

detect(ifnone = nil) {| obj | block } → obj or nil click to toggle source  find(ifnone = nil) {| obj | block } → obj or nil  detect(ifnone = nil) → an_enumerator  find(ifnone = nil) → an_enumerator 

Passes each entry in enum to block. Returns the first for which block is not false. If no object matches, calls ifnone and returns its result when it is specified, or returns nil otherwise.

find_all {| obj | block } → array click to toggle source select {| obj | block } → array find_all → an_enumerator select → an_enumerator 

Returns an array containing all elements of enum for which block is not false