public static void main(String[] args) {
int arr[]= {0,-1,2,-3,5,9,-5,10};
int max_ending_here=0;
int max_so_far=0;
int start =0;
int end=0;
for(int i=0;i< arr.length;i++)
{
max_ending_here=max_ending_here+arr[i];
if(max_ending_here<0)
{
max_ending_here=0;
}
if(max_so_far<max_ending_here){
max_so_far=max_ending_here;
}
}
System.out.println(max_so_far);
}
}
this program generates the max sum of sub array ..in this case its 19,using {5,9,-5,10}.. now i have to find the start and end index of this sub array ..how do i do that ??
Simple Approach: Run a loop for i from 0 to n – 1, where n is the size of the array. Now, we will run a nested loop for j from i to n – 1 and add the value of the element at index j to a variable currentMax. Lastly, for every subarray, we will check if the currentMax is the maximum sum of all contiguous subarrays.
This is a C program to solve this problem. I think logic is same for all languages so I posted this answer.
void findMaxSubArrayIndex(){
int n,*a;
int start=0,end=0,curr_max=0,prev_max=0,start_o=0,i;
scanf("%d",&n);
a = (int*)malloc(sizeof(int)*n);
for(i=0; i<n; i++) scanf("%d",a+i);
prev_max = a[0];
for(i=0; i<n; i++){
curr_max += a[i];
if(curr_max < 0){
start = i+1;
curr_max = 0;
}
else if(curr_max > prev_max){
end = i;
start_o = start;
prev_max = curr_max;
}
}
printf("%d %d \n",start_o,end);
}
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