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Finding the Date Difference

Tags:

r

sas

I've the following data:

ID GROUP     DATE 
A   GR1   12/01/2013
A   GR1   09/04/2014
A   GR1   01/03/2015
A   GR2   04/04/2015
A   GR2   08/21/2015
A   GR1   01/05/2016
A   GR1   06/28/2016
B   GR2   11/01/2013
B   GR2   06/04/2014
B   GR2   04/15/2015
B   GR3   11/04/2015
B   GR2   03/21/2016
B   GR2   07/05/2016
B   GR1   06/28/2016
C   GR2   01/16/2014
C   GR2   06/04/2014
C   GR2   04/15/2015
C   GR3   11/04/2015
C   GR2   03/21/2016
C   GR2   06/05/2016
C   GR1   06/28/2016

I want to get the difference the person remained in each group. So the new table will look like the following:

ID GROUP     DATE      Diff
A   GR1   12/01/2013
A   GR1   09/04/2014
A   GR1   01/03/2015    398
A   GR2   04/04/2015
A   GR2   08/21/2015    139
A   GR1   01/05/2016
A   GR1   06/28/2016    175
B   GR2   11/01/2013
B   GR2   06/04/2014
B   GR2   04/15/2015    530
B   GR3   11/04/2015
B   GR2   03/21/2016
B   GR2   07/05/2016    106
B   GR1   06/28/2016
C   GR2   01/16/2014
C   GR2   06/04/2014    
C   GR2   04/15/2015    454
C   GR3   11/04/2015
C   GR2   03/21/2016
C   GR2   01/05/2016    76
C   GR1   06/28/2016

THe value in column "Diff" 398 is coming by taking difference '01/03/2015' - '12/1/2013'. Similarly all other difference.

Now my question is how to get this difference? I can't take max(date)-min(date) at each group, because group are repeating at different period. Similarly I can't take first dot and last dot as in SAS.

I'll be extremely grateful if someone help me with the solution. I would prefer the solution in SAS as the data size is very large. SO will not hold in memory.

Regards,

like image 434
Beta Avatar asked Dec 11 '22 13:12

Beta


1 Answers

library(dplyr)
library(data.table)
df$xxx = rleidv(df[, c("ID","GROUP"),with = FALSE ])
df$DATE = as.Date(df$DATE, format = "%m/%d/%Y")
df %>% group_by(xxx) %>% mutate(diff = max(DATE) - min(DATE)) %>%
       ungroup(xxx) %>% mutate(xxx = NULL)
#     ID GROUP       DATE     diff
#   <chr> <chr>     <date>   <time>
#1      A   GR1 2013-12-01 398 days
#2      A   GR1 2014-09-04 398 days
#3      A   GR1 2015-01-03 398 days
#4      A   GR2 2015-04-04 139 days
#5      A   GR2 2015-08-21 139 days
#6      A   GR1 2016-01-05 175 days
#7      A   GR1 2016-06-28 175 days
#8      B   GR2 2013-11-01 530 days
#9      B   GR2 2014-06-04 530 days
#10     B   GR2 2015-04-15 530 days

using only data.table:

library(data.table)
df[, diff := max(DATE)-min(DATE),by = c("xxx")][,xxx:=NULL]
like image 58
joel.wilson Avatar answered Jan 03 '23 15:01

joel.wilson