Finding repeated values in multiple lists

Question

I am trying to find if any of the sublists in list1 has a repeated value, so i need to be told if a number in list1[0] is the same number in list[1] (which 20 is repeated)

the numbers represent coords and the coords of each item in list1 cannot over lap, if they do then i have a module that reruns a make a new list1 untill no coords are the smae

please help

    list1 = [[7, 20], [20, 31, 32], [66, 67, 68],[7, 8, 9, 2],
             [83, 84, 20, 86, 87], [144, 145, 146, 147, 148, 149]]

    x=0
    while x != 169:
        if list1.count(x) > 0:
        print ("repeat found")
    else:
        print ("no repeat found")
    x+=1

Answer 1

How about something like:

is_dup = sum(1 for l in list1 if len(set(l)) < len(l))
if is_dup > 0:
  print ("repeat found")
else:
  print ("no repeat found")

Another example using any:

any(len(set(l)) < len(l) for l in list1)

To check if only one item is repeated in all of the lists I would chain them and check. Credit to this answer for flattening a list of lists.

flattened = sum(list1, [])
if len(flattened) > len(set(flattened)):
  print ("dups")
else:
  print ("no dups")

I guess the proper way to flatten lists is to use itertools.chain which can be used as such:

flattened = list(itertools.chain(*list1))

This can replace the sum call I used above if that seems like a hack.