This may be a simple question, but I seem to be pulling my hair out to find an elegant solution here. I have two ActiveRecord model classes, with a has_one and belongs_to association between them:
class Item < ActiveRecord::Base
has_one :purchase
end
class Purchase < ActiveRecord::Base
belongs_to :item
end
I'm looking for an elegant way to find all Item objects, that have no purchase object associated with them, ideally without resorting to having a boolean is_purchased
or similar attribute on the Item.
Right now I have:
purchases = Purchase.all
Item.where('id not in (?)', purchases.map(&:item_id))
Which works, but seems inefficient to me, as it's performing two queries (and purchases could be a massive record set).
Running Rails 3.1.0
It's quite common task, SQL OUTER JOIN usually works fine for it. Take a look here, for example.
In you case try to use something like
not_purchased_items = Item.joins("LEFT OUTER JOIN purchases ON purchases.item_id = items.id").where("purchases.id IS null")
Found two other railsey ways of doing this:
Item.includes(:purchase).references(:purchase).where("purchases.id IS NULL")
Item.includes(:purchase).where(purchases: { id: nil })
Technically the first example works without the 'references' clause but Rails 4 spits deprecation warnings without it.
A more concise version of @dimuch solution is to use the left_outer_joins
method introduced in Rails 5:
Item.left_outer_joins(:purchase).where(purchases: {id: nil})
Note that in the left_outer_joins
call :purchase
is singular (it is the name of the method created by the has_one
declaration), and in the where
clause :purchases
is plural (here it is the name of the table that the id
field belongs to.)
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