Find the minimum of a list of dictionaries with respect to a specific key

Question

I have this :

[{'prisonniers': [], 'sécurité': '47'},{'prisonniers': [],'sécurité':'92'}, {'prisonniers': [], 'sécurité': '38'}]

And I need to put inside another list the dict which has the lowest 'sécurity', in this case, I need this:

myList = [{'prisonniers': [], 'sécurité': '38'}]

Answer 1

min function accepts an argument named key, it will find the minimum of an iterable based on key that can be callable. so, try this:

l = [{'prisonniers': [], 'sécurité': '47'},{'prisonniers': [],'sécurité':'92'}, {'prisonniers': [], 'sécurité': '38'}]

min(l, key=lambda x:x['sécurité'])

the output will be

{'prisonniers': [], 'sécurité': '38'}