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I know many ways how to find a substring: from start index to end index, between characters etc., but I have a problem which I don't know how to solve: I have a string like for example a path: folder1/folder2/folder3/new_folder/image.jpg and the second path: folder1/folder2/folder3/folder4/image2.png
And from this paths I want to take only the last parts: image.jpg and image2.png. How can I take a substring if I don't know when it starts (I don't know the index, but I can suppose that it will be after last / character), if many times one character repeats (/) and the extensions are different (.jpg and .png and even other)?
763
To get the substring after a specific character, call the substring() method, passing it the index after the character's index as a parameter. The substring method will return the part of the string after the specified character. Copied! We used the String.
The strrchr() function finds the last occurrence of c (converted to a character) in string . The ending null character is considered part of the string . The strrchr() function returns a pointer to the last occurrence of c in string .
First, we have printed the original string and the split word. We then performed the partition function to divide the string. This function will get a string after the substring occurrence. After performing the partition function on the initialized string, print the result in the last line of code.
Use os.path.basename() instead and not worry about the details.
os.path.basename() returns the filename portion of your path:
>>> import os.path >>> os.path.basename('folder1/folder2/folder3/new_folder/image.jpg') 'image.jpg' For a more generic string splitting problem, you can use str.rpartition() to split a string on a given character sequence counting from the end:
>>> 'foo:bar:baz'.rpartition(':') ('foo:bar', ':', 'baz') >>> 'foo:bar:baz'.rpartition(':')[-1] 'baz' and with str.rsplit() you can split multiple times up to a limit, again from the end:
>>> 'foo:bar:baz:spam:eggs'.rsplit(':', 3) ['foo:bar', 'baz', 'spam', 'eggs'] Last but not least, you could use str.rfind() to find just the index of a substring, searching from the end:
>>> 'foo:bar:baz'.rfind(':') 7 You can do this as well -
str_mine = 'folder1/folder2/folder3/new_folder/image.jpg' print str_mine.split('/')[-1] >> image.png If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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