I need to find out the 3rd maximum salary
for an employee for each department in a table
. if no 3rd maximum salary
exists then display 2nd maximum salary
. if no 2nd maximum salary
exist then find the highest salary
. How to achieve this result in sql-server
?
The table
structure is given below
create table employee1(empid int, empname varchar(10), deptid int, salary money)
insert into employee1
select 1,'a',1, 1000
union
select 1,'b',1, 1200
union
select 1,'c',1, 1500
union
select 1,'c',1, 15700
union
select 1,'d',2, 1000
union
select 1,'e',2, 1200
union
select 1,'g',3, 1500
I have tried the common way of getting the maximum salary for each category using row_number
function.
;with cte
as
(
select ROW_NUMBER( ) over( partition by deptid order by salary) as id, * from employee1
)
select * from cte
Here is a way to do this task using dense_rank() function. Query : select * from( select ename, sal, dense_rank() over(order by sal desc)r from Employee) where r=&n; To find to the 2nd highest sal set n = 2 To find 3rd highest sal set n = 3 and so on.
To find the highest salary in the table, write the following query. SELECT MAX(SALARY) FROM Employee; This will give you the output as 15000, i.e the highest salary in the table above.
Select EmpID,empname,deptid,salary
From (
Select *
,RN = Row_Number() over (Partition By deptid Order By Salary)
,Cnt = sum(1) over (Partition By deptid)
From employee1
) A
Where RN = case when Cnt<3 then Cnt else 3 end
Returns
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