Find min, max, and average of a list

Question

I am having hard time to figure out how to find min from a list for example

somelist = [1,12,2,53,23,6,17] 

how can I find min and max of this list with defining (def) a function

I do not want to use built-in function min

Answer 1

from __future__ import division  somelist =  [1,12,2,53,23,6,17]  max_value = max(somelist) min_value = min(somelist) avg_value = 0 if len(somelist) == 0 else sum(somelist)/len(somelist) 

If you want to manually find the minimum as a function:

somelist =  [1,12,2,53,23,6,17]   def my_min_function(somelist):     min_value = None     for value in somelist:         if not min_value:             min_value = value         elif value < min_value:             min_value = value     return min_value 

Python 3.4 introduced the statistics package, which provides mean and additional stats:

from statistics import mean, median  somelist =  [1,12,2,53,23,6,17] avg_value = mean(somelist) median_value = median(somelist) 

Answer 2

Return min and max value in tuple:

def side_values(num_list):     results_list = sorted(num_list)     return results_list[0], results_list[-1]   somelist = side_values([1,12,2,53,23,6,17]) print(somelist)