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I have a string: "www.google.com.sdg.jfh.sd"
I want to find the first ".s" string that is found after "sdg".
so I have the index of "sdg", by:
var start_index = str.indexOf("sdg"); now I need to find the first ".s" index that is found after "sdg"
any help appreciated!
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The indexOf() method returns the position of the first occurrence of specified character(s) in a string. Tip: Use the lastIndexOf method to return the position of the last occurrence of specified character(s) in a string.
JavaScript indexOf() Method: The indexOf() method is a built-in & case-sensitive method that returns the index of the first occurrence of the specified value in the calling string object. It will return -1 if no such value is found.
The “find” function has been used to get the index of the first occurrence of an alphabet “I”. This index number will be saved to the variable “index” and the print statement will display it on the shell.
To find the position of first occurrence of a string, you can use string. find() method. where string is the string in which you have to find the index of first occurrence of substring . start and end are optional and are starting and ending positions respectively in which substring has to be found.
There's a second parameter which controls the starting position of search:
String.prototype.indexOf(arg, startPosition); So you can do
str.indexOf('s', start_index); This code might be helpful
var string = "www.google.com.sdg.jfh.sd", preString = "sdg", searchString = ".s", preIndex = string.indexOf(preString), searchIndex = preIndex + string.substring(preIndex).indexOf(searchString); You can test it HERE
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