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What I need to do if Search a folder say C:\example
I then need to go through each file and check to see if it matches a few start characters so if files start
temp****.txt tempONE.txt tempTWO.txt So if the file starts with temp and has an extension .txt I would like to then put that file name into a File file = new File("C:/example/temp***.txt); so I can then read in the file, the loop then needs to move onto the next file to check to see if it meets as above.
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list() returns the array of files and directories in the directory defined by this abstract path name. The method returns null, if the abstract pathname does not denote a directory.
Interface FilenameFilter public interface FilenameFilter. Instances of classes that implement this interface are used to filter filenames. These instances are used to filter directory listings in the list method of class File , and by the Abstract Window Toolkit's file dialog component.
It searches or finds files from a file tree quickly. In the old days, we always use an error-prone recursive loop to walk a file tree. This Java 8 Files. find can save you a lot of time.
What you want is File.listFiles(FileNameFilter filter).
That will give you a list of the files in the directory you want that match a certain filter.
The code will look similar to:
// your directory File f = new File("C:\\example"); File[] matchingFiles = f.listFiles(new FilenameFilter() { public boolean accept(File dir, String name) { return name.startsWith("temp") && name.endsWith("txt"); } }); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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