I am able to find the duplicates out of DataTable rows. Like following:
var groups = table.AsEnumerable()
.GroupBy(r => new
{
c1 = r.Field<String>("Version"),
});
var tblDuplicates = groups
.Where(grp => grp.Count() > 1)
.SelectMany(grp => grp)
.CopyToDataTable();
Now, I want to merge all the duplicate records in to single and sum it's Value column value.
Pretty much like following:
DataTable with Duplicates:
Version Value
1 2
2 2
2 1
1 3
2 1
3 2
DataTable with no duplicates and Value summed.:
Version Value
1 5
2 4
3 2
I am aware about this link which does this with the help of reflection. http://forums.asp.net/t/1570562.aspx/1
Anyother way to do it?
Edit: However, if I have more than two columns, like five columns and I still want to do the sum on Value column and also need other columns data in resulatant summed datatable. How to do it? Here I get the Version and Value in my result DataTable. I want other columns with values also. Like following:
Version col1 col2 Value
1 A A 2
2 B B 2
2 B B 1
1 A A 3
2 B B 1
3 C C 2
var result = table.AsEnumerable()
.GroupBy(r => r.Field<string>("Version"))
.Select(g =>
{
var row = table.NewRow();
row.ItemArray = new object[]
{
g.Key,
g.Sum(r => r.Field<int>("Value"))
};
return row;
}).CopyToDataTable();
Edit:
If you want to keep other field, try below:
var result = table.AsEnumerable()
.GroupBy(r => new
{
Version = r.Field<String>("Version"),
Col1 = r.Field<String>("Col1"),
Col2 = r.Field<String>("Col2")
})
.Select(g =>
{
var row = g.First();
row.SetField("Value", g.Sum(r => r.Field<int>("Value")));
return row;
}).CopyToDataTable();
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With