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I'm looking to find the day of year for a POSIXct class object with lubridate. For example, 12-9-2015 is day 343.
It's easy to find the day of the week or month with lubridate:
> lubridate::wday("2015-12-09 04:27:56 EST", labels = T)
Wed
> lubridate::day("2015-12-09 04:27:56 EST")
9
Is there an easy way to do so for the day of the year? I've searched the documentation and other questions but have not (yet) found an answer.
549
Value. wday() returns the day of the week as a decimal number or an ordered factor if label is TRUE .
Lubridate is an R package that makes it easier to work with dates and times. Below is a concise tour of some of the things lubridate can do for you. Lubridate was created by Garrett Grolemund and Hadley Wickham, and is now maintained by Vitalie Spinu.
lubridate: Make Dealing with Dates a Little EasierFunctions to work with date-times and time-spans: fast and user friendly parsing of date-time data, extraction and updating of components of a date-time (years, months, days, hours, minutes, and seconds), algebraic manipulation on date-time and time-span objects.
To get the year from a date in R you can use the functions as. POSIXct() and format() . For example, here's how to extract the year from a date: 1) date <- as. POSIXct("02/03/2014 10:41:00", format = "%m/%d/%Y %H:%M:%S) , and 2) format(date, format="%Y") .
The correct function is yday, as in
lubridate::yday(Sys.time()) If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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