Find all except one in mongodb

Question

I want to skip one user particular by using _id and display all others users, I am trying below code its not working:

db.user.find(
    { _id: { $nin: ["5848e9ecaec0f31372816a26"] } },
    { username: 1 }
).pretty()

Answer 1

Use ObjectId for _id :

db.user.find( { _id: { $nin: [ObjectId("5848e9ecaec0f31372816a26")] } } )

Answer 2

Short answer: Use $ne for one user db.user.find( {_id:{$ne:"5848e9ecaec0f31372816a26"} }) .