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Filter a list of string using filter() method. filter() method accepts two parameters. The first parameter takes a function name or None and the second parameter takes the name of the list variable as values. filter() method stores those data from the list if it returns true, otherwise, it discards the data.
Short answer: To filter a list of lists for a condition on the inner lists, use the list comprehension statement [x for x in list if condition(x)] and replace condition(x) with your filtering condition that returns True to include inner list x , and False otherwise.
We can also use filter() with a string as an iterable sequence and can filter out characters from it.
Select a cell in the data table. On the Data tab of the Ribbon, in the Sort & Filter group, click Advanced, to open the Advanced Filter dialog box. For Action, select Filter the list, in-place.
This simple filtering can be achieved in many ways with Python. The best approach is to use "list comprehensions" as follows:
>>> lst = ['a', 'ab', 'abc', 'bac']
>>> [k for k in lst if 'ab' in k]
['ab', 'abc']
Another way is to use the filter function. In Python 2:
>>> filter(lambda k: 'ab' in k, lst)
['ab', 'abc']
In Python 3, it returns an iterator instead of a list, but you can cast it:
>>> list(filter(lambda k: 'ab' in k, lst))
['ab', 'abc']
Though it's better practice to use a comprehension.
[x for x in L if 'ab' in x]
# To support matches from the beginning, not any matches:
items = ['a', 'ab', 'abc', 'bac']
prefix = 'ab'
filter(lambda x: x.startswith(prefix), items)
Tried this out quickly in the interactive shell:
>>> l = ['a', 'ab', 'abc', 'bac']
>>> [x for x in l if 'ab' in x]
['ab', 'abc']
>>>
Why does this work? Because the in operator is defined for strings to mean: "is substring of".
Also, you might want to consider writing out the loop as opposed to using the list comprehension syntax used above:
l = ['a', 'ab', 'abc', 'bac']
result = []
for s in l:
if 'ab' in s:
result.append(s)
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