Filtering a list of (A, Option[B]) and extracting value from Option

Question

I have a List[(A, Option[B])]. I would like to filter out all of the tuples containing a None in the second element and then "unwrap" the Option, giving a List[A, B].

I am currently using this:

list.filter(_._2.isDefined).map(tup => (tup._1, tup._2.get))

Is there a better way (more concise)?

Answer 1

You can do it with pattern matching and collect:

list.collect { case (a, Some(b)) => (a, b) }