I've searched around a bit, but haven't found a good answer yet on how to filter out any entries into a map that have a value of None. Say I have a map like this:
val map = Map[String, Option[Int]]("one" -> Some(1), "two" -> Some(2), "three" -> None)
I'd like to end up returning a map with just the ("one", Some(1))
and ("two", Some(2))
pair. I understand that this is done with flatten when you have a list, but I'm not sure how to achieve the effect on a map without splitting it up into keys and values, and then trying to rejoin them.
If you're filtering out None
values, you might as well extract the Some
values at the same time to end up with a Map[String,Int]
:
scala> map.collect { case (key, Some(value)) => (key, value) } res0: scala.collection.immutable.Map[String,Int] = Map(one -> 1, two -> 2)
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