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Here is the form
form action="index.php" method="POST" enctype="multipart/form-data" >
<input type="file" name="image[]" multiple="multiple">
<input type="submit" value="upload">
</form>
I am trying to only run my code when only when if(!empty($_FILES['image'])){ but for some reason the array is not empty upon submitting no files and only clicking submit.
Here is the rest of the code if that will help, thanks.
<html>
Image Upload
<form action="index.php" method="POST" enctype="multipart/form-data" >
<input type="file" name="image[]" multiple="multiple">
<input type="submit" value="upload">
</form>
<?php
include 'connect.php';
if(!empty($_FILES['image'])){
echo $_FILES['image']['error'];
$allowed = array('jpg', 'gif', 'png', 'jpeg');
$count = 0;
foreach($_FILES['image']['name'] as $key => $name){
$image_name = $name;
$tmp = explode('.', $image_name);
$image_extn = strtolower(end($tmp)); //can only reference file
$image_temp = $_FILES['image']['tmp_name'][$count];
$filesize = filesize($_FILES['image']['tmp_name'][$count]);
$count = $count +1;
if(count($_FILES['image']['tmp_name']) > 5){
echo "You can upload a maximum of five files.";
break;
}
else if(in_array($image_extn, $allowed) === false){
echo $name." is not an allowed file type<p></p>";
}
else if($filesize > 1024*1024*0.3){
echo $name." is too big, can be a maximum of 3MB";
}
else{
$image_path = 'images/' . substr(md5($name), 0, 10) . '.' . $image_extn;
move_uploaded_file($image_temp, $image_path);
mysql_query("INSERT INTO store VALUES ('', '$image_name', '$image_path')") or die(mysql_error());
$lastid = mysql_insert_id();
$image_link = mysql_query("SELECT * FROM store WHERE id = $lastid");
$image_link = mysql_fetch_assoc($image_link);
$image_link = $image_link['image'];
echo "Image uploaded.<p></p> Your image: <p></p><a href = $image_link>$image_path</a>";
}
}
}
else{
echo "Please select an image.";
}
?>
894
This is how $_FILES array looks like when nothing uploaded
Array ( [image] => Array ( [name] => [type] => [tmp_name] => [error] => 4 [size] => 0 ) )
So it's never empty.
The error code 4 [error] => 4 indicates no file was uploaded and error code 0 indicates no error and file was uploaded so you can check
if($_FILES['image']['error']==0) {
// file uploaded, process code here
}
Here is another answer on SO.
152
Use the is_uploaded_file PHP function instead:
if(is_uploaded_file($_FILES['image']['tmp_name'])) {
//code here
}
http://php.net/manual/en/function.is-uploaded-file.php
8
You should first of all take a look into the PHP manual because - you're not the first one with that problem - the solution has been written in there:
If no file is selected for upload in your form, PHP will return
$_FILES['userfile']['size']as 0, and$_FILES['userfile']['tmp_name']as none.
So if you actually want to find out if any file for the image element has has been submitted, check for it:
$noFile = $_FILES['image']['size'][0] === 0
&& $_FILES['image']['tmp_name'][0] === '';
Yes, that simple it is.
The test you used:
empty($_FILE);
will only tell you if the whole form has been submitted or not. So an example in full:
$submitted = empty($_FILE);
if ($submitted) {
$noFile = $_FILES['image']['size'][0] === 0
&& $_FILES['image']['tmp_name'][0] === '';
if ($noFile) {
...
}
}
Check value is not null:
in_array(!null,$_FILES['field_name']['name'])
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