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File permissions on Linux/Unix with .NET Core

I am trying to learn how to set file permissions on Linux/Unix with .NET Core. I already found a question on here that points me in the direction of System.IO.FileSystem, but I can't seem to find any documentation on how to use it.

In a nutshell, I'd like to chmod a file 644 from a .NET Core application that only runs on Linux, but am at a loss on how to proceed.

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Steve Avatar asked Jul 16 '17 18:07

Steve


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2 Answers

At the moment, there is no built in API in .NET Core for this. However, the .NET Core team is working to make Mono.Posix available on .NET Core. This exposes API to do this kind of operation in managed code. See https://github.com/dotnet/corefx/issues/15289 and https://github.com/dotnet/corefx/issues/3186. You can try an early version of this API here: https://www.nuget.org/packages/Mono.Posix.NETStandard/1.0.0-beta1

    var unixFileInfo = new Mono.Unix.UnixFileInfo("test.txt");     // set file permission to 644     unixFileInfo.FileAccessPermissions =         FileAccessPermissions.UserRead | FileAccessPermissions.UserWrite         | FileAccessPermissions.GroupRead         | FileAccessPermissions.OtherRead; 

If you don't want to use Mono.Posix, you can implement this same functionality by invoking native code. Using P/Invoke, you can call the chmod function from libc. See man 2 chmod for more details on the native API.

using System; using System.IO; using System.Runtime.InteropServices; using static System.Console;  class Program {     [DllImport("libc", SetLastError = true)]     private static extern int chmod(string pathname, int mode);      // user permissions     const int S_IRUSR = 0x100;     const int S_IWUSR = 0x80;     const int S_IXUSR = 0x40;      // group permission     const int S_IRGRP = 0x20;     const int S_IWGRP = 0x10;     const int S_IXGRP = 0x8;      // other permissions     const int S_IROTH = 0x4;     const int S_IWOTH = 0x2;     const int S_IXOTH = 0x1;      static void Main(string[] args)     {         WriteLine("Setting permissions to 0755 on test.sh");         const int _0755 =             S_IRUSR | S_IXUSR | S_IWUSR             | S_IRGRP | S_IXGRP             | S_IROTH | S_IXOTH;         WriteLine("Result = " + chmod(Path.GetFullPath("test.sh"), (int)_0755));          WriteLine("Setting permissions to 0644 on sample.txt");         const int _0644 =             S_IRUSR | S_IWUSR             | S_IRGRP             | S_IROTH;         WriteLine("Result = " + chmod(Path.GetFullPath("sample.txt"), _0644));          WriteLine("Setting permissions to 0600 on secret.txt");         const int _0600 = S_IRUSR | S_IWUSR;         WriteLine("Result = " + chmod(Path.GetFullPath("secret.txt"), _0600));     } } 
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natemcmaster Avatar answered Sep 28 '22 22:09

natemcmaster


I solved this problem by just starting a new process and executing bash chmod commands.

Example:

public static void Exec(string cmd) {     var escapedArgs = cmd.Replace("\"", "\\\"");              using var process = new Process     {         StartInfo = new ProcessStartInfo         {             RedirectStandardOutput = true,             UseShellExecute = false,             CreateNoWindow = true,             WindowStyle = ProcessWindowStyle.Hidden,             FileName = "/bin/bash",             Arguments = $"-c \"{escapedArgs}\""         }     };      process.Start();     process.WaitForExit(); } 

and then:

Exec("chmod 644 /path/to/file.txt"); 

You can also use this Exec method to run any other type of bash commands.

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kspearrin Avatar answered Sep 28 '22 23:09

kspearrin