Consider the following code:
writer.c
mkfifo("/tmp/myfifo", 0660);
int fd = open("/tmp/myfifo", O_WRONLY);
char *foo, *bar;
...
write(fd, foo, strlen(foo)*sizeof(char));
write(fd, bar, strlen(bar)*sizeof(char));
reader.c
int fd = open("/tmp/myfifo", O_RDONLY);
char buf[100];
read(fd, buf, ??);
My question is:
Since it's not know before hand how many bytes will foo and bar have, how can I know how many bytes to read from reader.c?
Because if I, for example, read 10 bytes in reader and foo and bar are together less than 10 bytes, I will have them both in the same variable and that I do not want.
Ideally I would have one read function for every variable, but again I don't know before hand how many bytes will the data have.
I thought about adding another write instruction in writer.c between the write for foo and bar with a separator and then I would have no problem decoding it from reader.c. Is this the way to go about it?
Thanks.
The definition and operation of the FIFO method in industrial storage has to do with the way that goods are moved and is a simple concept: first in, first out. In other words, the first good or unit load to enter the warehouse is the first one out.
First in first out (FIFO) warehousing means exactly what it sounds like. It's an inventory control method in which the first items to come into the warehouse are the first items to leave. Similar to the service industry concept of “first come, first served”, the FIFO method focuses on products, not people.
Many of the other answers mention using some sort of protocol for your data and I believe this is the correct approach. This protocol can be as simple or complex as necessary. I have provided a couple of examples that you may find useful1.
In a simple case, you may only have a length byte followed by the data byte(s) (i.e. C string).
+--------------+ | length byte | +--------------+ | data byte(s) | +--------------+
Writer:
uint8_t foo[UCHAR_MAX+1];
uint8_t len;
int fd;
mkfifo("/tmp/myfifo", 0660);
fd = open("/tmp/myfifo", O_WRONLY);
memset(foo, UCHAR_MAX+1, 0);
len = (uint8_t)snprintf((char *)foo, UCHAR_MAX, "Hello World!");
/* The length byte is written first followed by the data. */
write(fd, len, 1);
write(fd, foo, strlen(foo));
Reader:
uint8_t buf[UCHAR_MAX+1];
uint8_t len;
int fd;
fd = open("/tmp/myfifo", O_RDONLY);
memset(buf, UCHAR_MAX+1, 0);
/* The length byte is read first followed by a read
* for the specified number of data bytes.
*/
read(fd, len, 1);
read(fd, buf, len);
In a more complex case, you may have a length byte followed by data bytes containing more than a simple C string.
+----------------+ | length byte | +----------------+ | data type byte | +----------------+ | data byte(s) | +----------------+
Common Header:
#define FOO_TYPE 100
#define BAR_TYPE 200
typedef struct {
uint8_t type;
uint32_t flags;
int8_t msg[20];
} __attribute__((aligned, packed)) foo_t;
typedef struct {
uint8_t type;
uint16_t flags;
int32_t value;
} __attribute__((aligned, packed)) bar_t;
Writer:
foo_t foo;
unsigned char len;
int fd;
mkfifo("/tmp/myfifo", 0660);
fd = open("/tmp/myfifo", O_WRONLY);
memset(&foo, sizeof(foo), 0);
foo.type = FOO_TYPE;
foo.flags = 0xDEADBEEF;
snprintf(foo.msg, 20-1, "Hello World!");
/* The length byte is written first followed by the data. */
len = sizeof(foo);
write(fd, len, 1);
write(fd, foo, sizeof(foo));
Reader:
uint8_t buf[UCHAR_MAX+1];
uint8_t len;
uint16_t type;
union data {
foo_t * foo;
bar_t * bar;
}
int fd;
fd = open("/tmp/myfifo", O_RDONLY);
memset(buf, UCHAR_MAX+1, 0);
/* The length byte is read first followed by a read
* for the specified number of data bytes.
*/
read(fd, len, 1);
read(fd, buf, len);
/* Retrieve the message type from the beginning of the buffer. */
memcpy(&type, buf, sizeof(type));
/* Process the data depending on the type. */
switch(type) {
case FOO_TYPE:
data.foo = (foo_t)buf;
printf("0x%08X: %s\n", data.foo.flags, data.foo.msg);
break;
case BAR_TYPE:
data.bar = (bar_t)buf;
printf("0x%04X: %d\n", data.bar.flags, data.bar.value);
break;
default:
printf("unrecognized type\n");
}
1 - This code was written from memory and is untested.
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