I want to convert three files with a single command. I used the following command:
-i "C:\fil1.mp4" -i "C:\file2.mp4" -i "C:\file3.mp4" -acodec libmp3lame -ab 32k -ar 22050 -ac 2 -b:v 128k -r 20 -s 176x144 -y file1.mp4 -acodec libmp3lame -ab 32k -ar 22050 -ac 2 -b:v 128k -r 20 -s 176x144 -y file2.mp4 -acodec libmp3lame -ab 32k -ar 22050 -ac 2 -b:v 128k -r 20 -s 176x144 -y file3.mp4
but it converts the first files with names fil1.mp4, fil2.mp4, fil3.mp4 but I want all files should be convert with its output file names.
Using -map helps with specifying which input goes with which output.
I used this code to convert multiple audio files:
ffmpeg -i infile1 -i infile2 -map 0 outfile1 -map 1 outfile2
also use -map_metadata to specify the metadata stream:
ffmpeg -i infile1 -i infile2 -map_metadata 0 -map 0 outfile1 -map_metadata 1 -map 1 outfile2
I wrote bash script for it.
You can modify as you want:
#!/bin/sh
BASE_DIR=$HOME/Videos/mov
OUTPUT_DIR=$BASE_DIR/avi
FILES=$(ls $BASE_DIR | grep .MOV)
for FILE in $FILES
do
FILENAME="${FILE:0:-4}"
ffmpeg -i $BASE_DIR/$FILE $OUTPUT_DIR/$FILENAME.avi
done
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