I have a JavaScript array like:
var myArray = ['a', 'x', 'b', 'x', 'x', 'p', 'y', 'x', 'x', 'b', 'x', 'x'];
I want to fetch only those elements of the array that come after 2 consequent occurrences of a particular element.
i.e. in the above array, I want to fetch all the elements that come after consequent 'x', 'x'
So my output should be:
'p'
'b'
I have a solution like :
var arrLength = myArray.length;
for (var i = 0; i < arrLength; i++) {
if(i+2 < arrLength && myArray[i] == 'x' && myArray[i+1] == 'x') {
console.log(myArray[i+2]);
}
};
This satisfies my needs, but it is not so generic.
For eg. if I have to check for 3 consequent occurrences, then again I have to add a condition inside if for myArray[i+2] == 'x'
and so on.
Could anyone provide a better way to fetch the elements?
The functional way would be to use recursion. With an ES6 spread, you can pretty much emulate the terseness of a truly 'functional' language :-)
var myArray = ['a', 'x', 'b', 'x', 'x', 'p', 'y', 'x', 'x', 'b', 'x', 'x'];
function reducer(acc, xs) {
if (xs.length > 2) {
if (xs[0] === xs[1]) {
// add the third element to accumulator
// remove first three elements from xs
// return reducer([xs[2], ...acc], xs.slice(3));
// or per Nina's question below
return reducer([xs[2], ...acc], xs.slice(1));
} else {
// remove first element from xs and recurse
return reducer(acc, xs.slice(1))
}
} else {
return acc;
}
}
console.log(reducer([], myArray));
A generic straight forward approach for any comparable content.
function getParts(array, pattern) {
return array.reduce(function (r, a, i) {
i >= pattern.length && pattern.every(function (b, j) {
return b === array[i + j - pattern.length];
}) && r.push(a);
return r;
}, []);
}
function p(o) {
document.write('<pre>' + JSON.stringify(o, 0, 4) + '</pre>');
}
p(getParts(['a', 'x', 'x', 'x', 'x', 'p', 'y', 'x', 'x', 'b', 'x', 'x'], ['x', 'x']));
p(getParts(['a', 'x', 'b', 'x', 'x', 'p', 'y', 'x', 'x', 'b', 'x', 'x'], ['a', 'x', 'b']));
p(getParts(['a', 'b', 'c', 'd', 'z', 'y', 'a', 'b', 'c', 'd', 'x', 'x'], ['a', 'b', 'c', 'd']));
p(getParts([41, 23, 3, 7, 8, 11, 56, 33, 7, 8, 11, 2, 5], [7, 8, 11]));
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