Fastest way to sort each row in a pandas dataframe

Question

I need to find the quickest way to sort each row in a dataframe with millions of rows and around a hundred columns.

So something like this:

A   B   C   D
3   4   8   1
9   2   7   2

Needs to become:

A   B   C   D
8   4   3   1
9   7   2   2

Right now I'm applying sort to each row and building up a new dataframe row by row. I'm also doing a couple of extra, less important things to each row (hence why I'm using pandas and not numpy). Could it be quicker to instead create a list of lists and then build the new dataframe at once? Or do I need to go cython?

Answer 1

I think I would do this in numpy:

In [11]: a = df.values

In [12]: a.sort(axis=1)  # no ascending argument

In [13]: a = a[:, ::-1]  # so reverse

In [14]: a
Out[14]:
array([[8, 4, 3, 1],
       [9, 7, 2, 2]])

In [15]: pd.DataFrame(a, df.index, df.columns)
Out[15]:
   A  B  C  D
0  8  4  3  1
1  9  7  2  2

---

I had thought this might work, but it sorts the columns:

In [21]: df.sort(axis=1, ascending=False)
Out[21]:
   D  C  B  A
0  1  8  4  3
1  2  7  2  9

Ah, pandas raises:

In [22]: df.sort(df.columns, axis=1, ascending=False)

ValueError: When sorting by column, axis must be 0 (rows)

Answer 2

To Add to the answer given by @Andy-Hayden, to do this inplace to the whole frame... not really sure why this works, but it does. There seems to be no control on the order.

    In [97]: A = pd.DataFrame(np.random.randint(0,100,(4,5)), columns=['one','two','three','four','five'])

    In [98]: A
    Out[98]: 
    one  two  three  four  five
    0   22   63     72    46    49
    1   43   30     69    33    25
    2   93   24     21    56    39
    3    3   57     52    11    74

    In [99]: A.values.sort
    Out[99]: <function ndarray.sort>

    In [100]: A
    Out[100]: 
    one  two  three  four  five
    0   22   63     72    46    49
    1   43   30     69    33    25
    2   93   24     21    56    39
    3    3   57     52    11    74

    In [101]: A.values.sort()

    In [102]: A
    Out[102]: 
    one  two  three  four  five
    0   22   46     49    63    72
    1   25   30     33    43    69
    2   21   24     39    56    93
    3    3   11     52    57    74
    In [103]: A = A.iloc[:,::-1]

    In [104]: A
    Out[104]: 
    five  four  three  two  one
    0    72    63     49   46   22
    1    69    43     33   30   25
    2    93    56     39   24   21
    3    74    57     52   11    3

I hope someone can explain the why of this, just happy that it works 8)