Fastest way to generate a random boolean

Question

So there is several ways of creating a random bool in C#:

• Using Random.Next(): rand.Next(2) == 0
• Using Random.NextDouble(): rand.NextDouble() > 0.5

Is there really a difference? If so, which one actually has the better performance? Or is there another way I did not see, that might be even faster?

Answer 1

The first option - rand.Next(2) executes behind the scenes the following code:

if (maxValue < 0) {     throw new ArgumentOutOfRangeException("maxValue",         Environment.GetResourceString("ArgumentOutOfRange_MustBePositive", new object[] { "maxValue" })); } return (int) (this.Sample() * maxValue); 

and for the second option - rand.NextDouble():

return this.Sample(); 

Since the first option contains maxValue validation, multiplication and casting, the second option is probably faster.