The script has to verify if one predefined IP is present in a big array of IPs. Currently I code that function like this (saying that "ips" is my array of IP and "ip" is the predefined ip)
ips.each do |existsip|
if ip == existsip
puts "ip exists"
return 1
end
end
puts "ip doesn't exist"
return nil
Is there a faster way to do the same thing?
Edit : I might have wrongly expressed myself. I can do array.include? but what I'd like to know is : Is array.include? the method that will give me the fastest result?
You can use Set. It is implemented on top of Hash and will be faster for big datasets - O(1).
require 'set'
s = Set.new ['1.1.1.1', '1.2.3.4']
# => #<Set: {"1.1.1.1", "1.2.3.4"}>
s.include? '1.1.1.1'
# => true
You could use the Array#include method to return you a true/false.
http://ruby-doc.org/core-1.9.3/Array.html#method-i-include-3F
if ips.include?(ip) #=> true
puts 'ip exists'
else
puts 'ip doesn\'t exist'
end
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