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What is the fastest way to replace all instances of a string/character in a string in JavaScript? A while, a for-loop, a regular expression?
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Use the replace() method to replace multiple characters in a string, e.g. str. replace(/[. _-]/g, ' ') . The first parameter the method takes is a regular expression that can match multiple characters.
3.1 The difference between replaceAll() and replace()If search argument is a string, replaceAll() replaces all occurrences of search with replaceWith , while replace() only the first occurence. If search argument is a non-global regular expression, then replaceAll() throws a TypeError exception.
replace() , we can replace a specific character. If we want to remove that specific character, replace that character with an empty string. The str. replace() method will replace all occurrences of the specific character mentioned.
The easiest would be to use a regular expression with g flag to replace all instances:
str.replace(/foo/g, "bar") This will replace all occurrences of foo with bar in the string str. If you just have a string, you can convert it to a RegExp object like this:
var pattern = "foobar", re = new RegExp(pattern, "g"); Try this replaceAll: http://dumpsite.com/forum/index.php?topic=4.msg8#msg8
String.prototype.replaceAll = function(str1, str2, ignore) { return this.replace(new RegExp(str1.replace(/([\/\,\!\\\^\$\{\}\[\]\(\)\.\*\+\?\|\<\>\-\&])/g,"\\$&"),(ignore?"gi":"g")),(typeof(str2)=="string")?str2.replace(/\$/g,"$$$$"):str2); } It is very fast, and it will work for ALL these conditions that many others fail on:
"x".replaceAll("x", "xyz"); // xyz "x".replaceAll("", "xyz"); // xyzxxyz "aA".replaceAll("a", "b", true); // bb "Hello???".replaceAll("?", "!"); // Hello!!! Let me know if you can break it, or you have something better, but make sure it can pass these 4 tests.
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