Faking a closure's function name

Question

Leaving out a long story, I have a scenario like this:

class Foo {

  function doSomething() {
    print "I was just called from " . debug_backtrace()[1]['function'];
  }

  function triggerDoSomething()
  {
    // This outputs "I was just called from triggerDoSomething".  
    // This output makes me happy.
    $this->doSomething();
  }

  function __call($method, $args)
  {
    // This way outputs "I was just called from __call"
    // I need it to be "I was just called from " . $method
    $this->doSomething();

    // This way outputs "I was just called from {closure}"
    // Also not what I need.
    $c = function() { $this->doSomething() };
    $c();

    // This causes an infinite loop
    $this->$method = function() { $this->doSomething() };
    $this->$method();
  }
}

In the case that I call $foo->randomFunction(), I need the the output to read "I was just called from randomFunction"

Is there a way to name a closure or approach this problem differently?

Note: I cannot change the doSomething function. It is a sample of third-party code I'm calling that considers the function name of who called it in order to do something.

Answer 1

you can pass the name to doSomething() like

$this->doSomething($method);

or with closure like

$c = function($func_name) { $this->doSomething($func_name); };
$c($method);

and in doSomething you can use that parameter.

function doSomething($method) {
    print "I was just called from " . $method;
}