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Is there a function to extract the extension from a filename?
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We can use Python os module splitext() function to get the file extension. This function splits the file path into a tuple having two values - root and extension.
py extension contain the Python source code. The Python language has become very famous language now a days. It can be used for system scripting, web and software development and mathematics.
Yes. Use os.path.splitext(see Python 2.X documentation or Python 3.X documentation):
>>> import os >>> filename, file_extension = os.path.splitext('/path/to/somefile.ext') >>> filename '/path/to/somefile' >>> file_extension '.ext' Unlike most manual string-splitting attempts, os.path.splitext will correctly treat /a/b.c/d as having no extension instead of having extension .c/d, and it will treat .bashrc as having no extension instead of having extension .bashrc:
>>> os.path.splitext('/a/b.c/d') ('/a/b.c/d', '') >>> os.path.splitext('.bashrc') ('.bashrc', '') If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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