extract server name from git clone URL

Question

I have this

$ cat test.sh
echo "https://bitbucket.dev.global.server.com/scm/xyz/abd.git"
echo "ssh://[email protected]:6699/xyz/abc.git"
echo "http://bitbucket.dev.global.server.com/abc"
echo "ssh://[email protected]/xyz/abc"
echo "http://bitbucket.dev.global.server.com"
echo "ssh://[email protected]/xyz/abc.git"

I want an one liner command (preferably sed command) that will extract the server name from the URL. e.g.

bitbucket.dev.global.server.com

I tried this but it doesn't work

$ ./test.sh | sed 's/\(\/\/\|\@\)/&\n/;s/.*\n//;s/\(\:\|\/\)/\n&/;s/\n.*//'
bitbucket.dev.global.server.com
[email protected]
bitbucket.dev.global.server.com
[email protected]
bitbucket.dev.global.server.com
[email protected]

It still got the user and @ symbol. How to do this?

Answer 1

I want an one liner command (preferably sed command)

Since you requested a sed one-liner, you can try this:

./test.sh | sed -E 's|.*://([^/@:]+@)?([^/@:]+).*|\2|'

which outputs this:

bitbucket.dev.global.server.com
bitbucket.dev.global.server.com
bitbucket.dev.global.server.com
bitbucket.dev.global.server.com
bitbucket.dev.global.server.com
bitbucket.dev.global.server.com

Explanation:

./test.sh | sed -E '
  s| .*://        # Match all up to "://"
     ([^/@:]+@)?  # Match "user@" or "git@"
     ([^/@:]+)    # The hostname
     .*           # Match all after the hostname and discard it
  |\2|'          # Replace full match with hostname, and then it's done

Answer 2

Try this, using perl, sed like syntax:

bash test.sh | perl -pe 's|.*://(?:\w+@)?([\w.]+)/?.*|\1|'

The regular expression matches as follows:

Node	Explanation
.*	any character except \n (0 or more times (matching the most amount possible))
://	'://'
(?:	group, but do not capture (optional (matching the most amount possible)):
\w+	word characters (a-z, A-Z, 0-9, _) (1 or more times (matching the most amount possible))
@	@
)?	end of grouping
(	group and capture to \1:
[\w.]+	any character of: word characters (a-z, A-Z, 0-9, _), '.' (1 or more times (matching the most amount possible))
)	end of \1
/?	'/' (optional (matching the most amount possible))
.*	any character except \n (0 or more times (matching the most amount possible))

or with GNU grep in PCRE mode:

bash test.sh | grep -oP '://(?:\w+@)?\K[\w.]+(?>=/)?' 

The regular expression matches as follows:

Node	Explanation
://	'://'
(?:	group, but do not capture (optional (matching the most amount possible)):
\w+	word characters (a-z, A-Z, 0-9, _) (1 or more times (matching the most amount possible))
@	@
)?	end of grouping
\K	resets the start of the match (what is Kept) as a shorter alternative to using a look-behind assertion: look arounds and Support of \K in regex
[\w.]+	any character of: word characters (a-z, A- Z, 0-9, _), '.' (1 or more times (matching the most amount possible))
(?>	match (and do not backtrack afterwards) (optional (matching the most amount possible)):
=/	'=/'
)?	end of look-ahead

---

yields:

bitbucket.dev.global.server.com
bitbucket.dev.global.server.com
bitbucket.dev.global.server.com
bitbucket.dev.global.server.com
bitbucket.dev.global.server.com
bitbucket.dev.global.server.com