How can I extract the extension of a file given a file path as a character? I know I can do this via regular expression regexpr("\\.([[:alnum:]]+)$", x)
, but wondering if there's a built-in function to deal with this?
The function splitext() in os. path allows you to separate the root and extension of a specified file path. A tuple made up of the root string and the extension string is the function's output.
To extract filename from the file, we use “GetFileName()” method of “Path” class. This method is used to get the file name and extension of the specified path string. The returned value is null if the file path is null. Syntax: public static string GetFileName (string path);
Use the os. path Module to Extract Extension From File in Python. Use the pathlib Module to Extract Extension From File in Python.
This is the sort of thing that easily found with R basic tools. E.g.: ??path.
Anyway, load the tools
package and read ?file_ext
.
Let me extend a little bit great answer from https://stackoverflow.com/users/680068/zx8754
Here is the simple code snippet
# 1. Load library 'tools' library("tools") # 2. Get extension for file 'test.txt' file_ext("test.txt")
The result should be 'txt'.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With