Given a vector A defined in Matlab by:
A = [ 0
0
1
0
0 ];
we can extract its dimensions using:
size(A);
Apparently, we can achieve the same things in Julia using:
size(A)
Just that in Matlab we are able to extract the dimensions in a vector, by using:
[n, m] = size(A);
irrespective to the fact whether A is one or two-dimensional, while in Julia A, size (A) will return only one dimension if A has only one dimension.
How can I do the same thing as in Matlab in Julia, namely, extracting the dimension of A, if A is a vector, in a vector [n m]. Please, take into account that the dimensions of A might vary, i.e. it could have sometimes 1 and sometimes 2 dimensions.
A = zeros(3,5)
sz = size(A)
returns a tuple (3,5)
. You can refer to specific elements like sz[1]
. Alternatively,
m,n = size(A,1), size(A,2)
This works even if A
is a column vector (i.e., one-dimensional), returning a value of 1
for n
.
This will achieve what you're expecting:
n, m = size(A); #or
(n, m) = size(A);
If size(A)
is a one dimensional Tuple
, m
will not be assigned, while n
will receive length(A)
. Just be sure to catch that error, otherwise your code may stop if running from a script.
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