I would like to have an R expression
in a ggplot2
facet label.
Let's say I'm plotting the tips
data.frame
:
library(reshape2)
> head(tips)
total_bill tip sex smoker day time size
1 16.99 1.01 Female No Sun Dinner 2
2 10.34 1.66 Male No Sun Dinner 3
3 21.01 3.50 Male No Sun Dinner 3
4 23.68 3.31 Male No Sun Dinner 2
5 24.59 3.61 Female No Sun Dinner 4
6 25.29 4.71 Male No Sun Dinner 4
as follows:
library(ggplot2)
sp <- ggplot(tips, aes(x=total_bill, y=tip/total_bill)) +
geom_point(shape=1) +
facet_wrap(~sex, ncol = 1)
Instead of having "Female" and "Male" as facet labels I would like to have:
"Female subjects" and "Male subjects", respectively. As far as I know italicizing a label in R is achieved through the expression
function, but I don't know how to combine that with facet_wrap
.
The following works for R 4.0.3 and ggplot2 3.3.2
library(ggplot2)
data(tips, package="reshape2")
tips$sex = as.character(tips$sex)
sp <- ggplot(tips, aes(x=total_bill, y=tip/total_bill)) +
geom_point(shape=1) +
facet_wrap(~sex, ncol = 1, labeller = label_bquote(italic(.(sex))~subjects))
sp
It uses label_bquote
as suggested by @Stéphane Laurent but does not require converting levels into the correct character within the bquote which failed for me.
As of ggplot2
2.1.0
:
data(tips, package="reshape2")
library(ggplot2)
ggplot(tips, aes(x=total_bill, y=tip/total_bill)) +
geom_point(shape=1) +
facet_wrap(~sex, ncol=1,
labeller=label_bquote(.(levels(tips$sex)[sex])~subjects))
Looks overly complicated, but works. You'll have to use facet_grid
though.
make_label <- function(value) {
x <- as.character(value)
bquote(italic(.(x))~subjects)
}
plot_labeller <- function(variable, value) {
do.call(expression, lapply(levels(value), make_label))
}
ggplot(tips, aes(x=total_bill, y=tip/total_bill)) +
geom_point(shape=1) +
facet_grid(.~sex, labeller = plot_labeller)
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