I want to move a series of app.use()
calls into its own module. The easiest way to encapsulate this is to expose a function(app)
in the exports, but I feel that handing over the app
object is too much of an opaque interface.
I would like to expose a middleware to be app.use()
'd from outside the module. I need to chain/compose the middlewares used internally.
Is there a stylish way of doing this, or an alternative? What's the easiest way of going about it? Anything I should avoid?
Express middleware are functions that execute during the lifecycle of a request to the Express server. Each middleware has access to the HTTP request and response for each route (or path) it's attached to. In fact, Express itself is compromised wholly of middleware functions.
Express provides a built in middleware function express. static . Static files are those files that a client downloads from a server. It is the only middleware function that comes with Express framework and we can use it directly in our application.
Here we have two middleware functions attached to the route with route path /products .
Express is a routing and middleware web framework that has minimal functionality of its own: An Express application is essentially a series of middleware function calls.
This answer is a little late, but here it goes anyway...
// composedMiddleware.js
const express = require('express')
const ware1 = (req, res, next)=>{...}
const ware2 = (req, res, next)=>{...}
const router = express.Router()
router.use(ware1)
router.use(ware2)
export default router
// app.js
const composedMiddleWare = require('./composedMiddleware.js')
app.get('/something', (req, res, next)=>{...})
app.get('/something', composedMiddleWare)
If the code isn't self-explanatory, then just note that routers are also middleware. Or, to put it more precisely, "a router behaves like middleware itself, so you can use it as an argument to app.use()" ref.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With