Export more than one variable in ES6?

Question

I'm trying to export more than one variable in ES6:

exports.js

var TestObject = Parse.Object.extend('TestObject') var Post = Parse.Object.extend('Post')  export default TestObject export Post 

main.js:

import TestObject from '../store' import Post from '../store'  var testObject = new TestObject() // use Post in the same way testObject.save(json).then(object => {   console.log('yay! it worked', object) }) 

I understand that there's only one default value so I only used default in the first item.

However, I get this error message:

Module build failed: SyntaxError: /home/alex/node/my-project/src/store/index.js: Unexpected token (9:7)    7 |     8 | export default TestObject >  9 | export Post 

Maybe I'm doing it the wrong way?

Answer 1

That is not valid syntax. You can do

export { Post } 

or even just

export var Post = Parse.Object.extend('Post') 

or shorten the whole file to

export default Parse.Object.extend('TestObject') export var Post = Parse.Object.extend('Post') 

Your imports are also incorrect, you'll want to do

import TestObject, { Post } from '../store' 

This is if you really want a single default export and a separate named export. You can also just make two named exports and have no default if you want, e.g.

export var TestObject = Parse.Object.extend('TestObject'); export var Post = Parse.Object.extend('Post'); 

or

var TestObject = Parse.Object.extend('TestObject'); var Post = Parse.Object.extend('Post'); export { TestObject, Post }; 

and import with

import { TestObject, Post } from '../store'