Is there any way to implement an interface explicitly using an automatic property? For instance, consider this code:
namespace AutoProperties
{
interface IMyInterface
{
bool MyBoolOnlyGet { get; }
}
class MyClass : IMyInterface
{
static void Main(){}
public bool MyBoolOnlyGet { get; private set; } // line 1
//bool IMyInterface.MyBoolOnlyGet { get; private set; } // line 2
}
}
This code compiles. However, if you replace line 1 with line 2 it does not compile.
(It's not that I need to get line 2 working - I'm just curious.)
An implicit interface implementation is where you have a method with the same signature of the interface. An explicit interface implementation is where you explicitly declare which interface the method belongs to.
Which statement correctly defines Interfaces in C#.NET? Explanation: Leaving all options only option 'a' is correct as interfaces can be inherited i.e inheritance can be performed in csharp . net.
In C#, an interface can be defined using the interface keyword. An interface can contain declarations of methods, properties, indexers, and events. However, it cannot contain fields, auto-implemented properties.
No, we can't declare variables, constructors, properties, and methods in the interface. no,interface cannot contains fields.
Indeed, that particular arrangement (explicit implementation of a get-only interface property by an automatically implemented property) isn't supported by the language. So either do it manually (with a field), or write a private auto-implemented prop, and proxy to it. But to be honest, by the time you've done that you might as well have used a field...
private bool MyBool { get;set;}
bool IMyInterface.MyBoolOnlyGet { get {return MyBool;} }
or:
private bool myBool;
bool IMyInterface.MyBoolOnlyGet { get {return myBool;} }
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