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expected identifier before string constant

Having a program like this:

#include <iostream>
#include <string>
using namespace std;
class test
{
public:
    test(std::string s):str(s){};
private:
    std::string str;
};

class test1
{
public:
    test tst_("Hi");
};

int main()
{
    return 1;
}

…why am I getting the following when I execute

g++ main.cpp

main.cpp:16:12: error: expected identifier before string constant
main.cpp:16:12: error: expected ‘,’ or ‘...’ before string constant
like image 504
rahman Avatar asked Apr 07 '12 05:04

rahman


2 Answers

You can not initialize tst_ where you declare it. This can only be done for static const primitive types. Instead you will need to have a constructor for class test1.

EDIT: below, you will see a working example I did in ideone.com. Note a few changes I did. First, it is better to have the constructor of test take a const reference to string to avoid copying. Second, if the program succeeds you should return 0 not 1 (with return 1 you get a runtime error in ideone).

#include <iostream>
#include <string>
using namespace std;
class test
{
public:
    test(const std::string& s):str(s){};
private:
    std::string str;
};
 
class test1
{
public:
    test1() : tst_("Hi") {}
    test tst_;
};
 
int main()
{
    return 0;
}
like image 168
Ivaylo Strandjev Avatar answered Nov 01 '22 10:11

Ivaylo Strandjev


There is another and more simplified way of doing what you want:Just change your statement from test tst_("Hi"); to test tst_{"Hi"}; and it will work. Below is the modified code and it works as expected.

#include <iostream>
#include <string>
using namespace std;
class test
{
public:
    test(std::string s):str(s){cout<<"str is: "<<s;}
private:
    std::string str;
};

class test1
{
public:
    test tst_{"Hi"};
};

int main()
{   test1 obj;
    return 0;
}

Note that i have just changed test tst_("Hi"); to test tst_{"Hi"}; and everything else is exactly the same. Just for confirmation that this works i have added one cout to check that it initialize the str variable correctly. I think this one line solution is more elegant(at least to me) and and up to date with the new standard.

like image 1
Anoop Rana Avatar answered Nov 01 '22 09:11

Anoop Rana