Exit all functions from code in inner function

Question

If I have nested functions in C#, how to exit from both function at once when executing inner function code. (Return; only exits from executing function.)

public void Function1()
{
    Function2();
}

public void Function2()
{
    if (1 == 1)
    {       
        //Exit from both functions
    }
}

Answer 1

Use return codes instead of void functions. Function1 can return if Function2 fails like so:

public void Function1()
{
    if (Function2() == false)
        return;

    // do other code if Function2 succeeded
}

public bool Function2()
{
    if (1 == 1)
    {
        return false;
    }
    else
    {
        return true;
    }
}

Answer 2

The only way to return from a stack of functions simultaneously is to throw an exception. An exception will work it's way down the call stack until it finds an appropriate handler.

public class MyException : Exception
{
}

public void FunctionZero()
{
   try
   {
      Trace.WriteLine("Function0 - Calling Function 1");
      Function1();
      Trace.WriteLine("Function0 - Function1 has returned");
   }
   catch(MyExceptionType ex)
   {
      Trace.WriteLine("Function0 - in the exception handler");
   }
}

public void Function1()
{
    Trace.WriteLine("Function1 - Calling Function 2");
    Function2();
    Trace.WriteLine("Function1 - Function2 has returned");
}

public void Function2()
{
    if (1==1)
    {
       // This will jump to the exception handler in function zero
       Trace.WriteLine("Function2 - throwing an exception");
       throw new MyException();
    }
}

Thiw will create the following trace output

Function0 - Calling Function 1

Function1 - Calling Function 2

Function2 - Throwing an exception

Function0 - In the exception handler

While you CAN do this, it's not necessarily a good idea. Standard coding practice is for Exceptions only to be used in exceptional circumstances, and not for normal flow control.