Existential type or type parameter bound failure

Question

I have an F-bounded type Sys:

trait Sys[S <: Sys[S]]

And some trait which take it as type parameter:

trait Foo[S <: Sys[S]]

Suppose I have a method to be invoked with a Foo:

def invoke[S <: Sys[S]](foo: Foo[S]) = ()

Suppose I have a model update type, and a sub-type which carries a Foo:

sealed trait Update
case class Opened[S <: Sys[S]](foo: Foo[S]) extends Update

A helper function to register a model observer:

def observe(pf: PartialFunction[Update, Unit]) = ()

---

Now the following fails:

observe {
  case Opened(foo) => invoke(foo)
}

with

<console>:16: error: inferred type arguments [Any] do not conform to method invoke's
                     type parameter bounds [S <: Sys[S]]
                case Opened(foo) => invoke(foo)
                                    ^

How can I fix the partial function, if Sys, Foo, invoke, Update, Opened and observe are given. It is allowed to add a value or type member to Foo.

Answer 1

How about move type parameter for Foo trait to type variable:

trait Sys[S <: Sys[S]]
trait Foo { type S <: Sys[S] }

sealed trait Update
case class Opened(foo: Foo) extends Update

def invoke(foo: Foo) = ()
def observe(pf: PartialFunction[Update, Unit]) = ()

observe {
  case Opened(foo) => invoke(foo)
}

Update:

You are absolutely right. And for all new type substitution you need to define alias for move type parameter to body.

Type alias example:

trait Sys[S <: Sys[S]]
class A extends Sys[A]
class B extends Sys[B]

trait Foo { type S <: Sys[S] }
trait Boo { type S <: Sys[S] } 

object module_A{
  type Foo = com.company.Foo { type S <: A }
  type Boo = com.company.Boo { type S <: A }
}

def invoke(foo: module_A.Foo, boo: module_A.Boo) = ()