Execute command for every file in the current dir

Question

How can i execute a certain command for every file/folder in the current folder?

I've started with this as a base script, but this seems that its only working when using temporary files, and i dont really like the ideea. Is there any other way?

FOLDER="."; DIRS=`ls -1 "$FOLDER">/tmp/DIRS`;  echo >"/tmp/DIRS1"; while read line ; do     SIZE=`du "$FOLDER$line"`;     echo $SIZE>>"/tmp/DIRS1"; done < "/tmp/DIRS"; 

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For anyone interested, i wanted to make a list of folders, sorted by their size. Here is the final result

FOLDER="$1"; for f in $FOLDER/*; do    du -sb "$f"; done | sort -n | sed "s#^[0-9]*##" | sed "s#^[^\./]*##" | xargs -L 1 du -sh | sed "s|$FOLDER||"; 

which leads to du -sb $FOLDER/* | sort -n | sed "s#^[0-9]*##" | sed "s#^[^\./]*##" | xargs -L 1 du -sh | sed "s|$FOLDER||";

Answer 1

Perhaps xargs, which reinvokes the command specified after it for each additional line of parameters received on stdin...

ls -1 $FOLDER | xargs du 

But, in this case, why not...

du * 

...? Or...

for X in *; do     du $X done 

(Personally, I use zsh, where you can modify the glob pattern to only find say regular files, or only directories, only symlinks etc - I'm pretty sure there's something similar in bash - can dig for details if you need that).

Am I missing part of your requirement?

Answer 2

The find command will let you execute a command for each item it finds, too. Without further arguments it will find all files and folders in the current directory, like this:

$ find -exec du -h {} \; 

The {} part is the "variable" where the match is placed, here as the argument to du. \; ends the command.