How would I make my server run a php script by triggering it manually using php? Basically I have a pretty big cronjob file that is ran every 2 hours, but I want to be able to trigger the file manually myself without having to wait for it to load (i want it to be done on the server's side).
EDIT: I want to execute the file from a php file... Not command line.
Answer: Use the PHP header() Function You can simply use the PHP header() function to redirect a user to a different page. The PHP code in the following example will redirect the user from the page in which it is placed to the URL http://www.example.com/another-page.php . You can also specify relative URLs.
<? php include ('Scripts/Php/connection. txt'); //The connection. txt script is executed inside the current file ?>
Use file_get_contents , to open up the file, append it to the second file like so: $secondFile = file_get_contents('http://www.sample.com/includeThis.php'); file_put_contents('your_file', $secondFile, FILE_APPEND); This will work if you want to put it at the end of your file.
You can invoke a PHP script manually from the command line
hello.php <?php echo 'hello world!'; ?> Command line: php hello.php Output: hello world!
See the documentation: http://php.net/manual/en/features.commandline.php
EDIT OP edited the question to add a critical detail: the script is to be executed by another script.
There are a couple of approaches. First and easiest, you could simply include the file. When you include a file, the code within is "executed" (actually, interpreted). Any code that is not within a function or class body will be processed immediately. Take a look at the documentation for include
(docs) and/or require
(docs) (note: include_once
and require_once
are related, but different in an important way. Check out the documents to understand the difference) Your code would look like this:
include('hello.php'); /* output hello world! */
Second and slightly more complex is to use shell_exec
(docs). With shell_exec
, you will call the php binary and pass the desired script as the argument. Your code would look like this:
$output = shell_exec('php hello.php'); echo "<pre>$output</pre>"; /* output hello world! */
Finally, and most complex, you could use the CURL library to call the file as though it were requested via a browser. Check out the CURL library documentation here: http://us2.php.net/manual/en/ref.curl.php
$ch = curl_init(); curl_setopt($ch, CURLOPT_URL, "http://www.myDomain.com/hello.php"); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true) $output = curl_exec($ch); curl_close($ch); echo "<pre>$output</pre>"; /* output hello world! */
Documentation for functions used
include
: http://us2.php.net/manual/en/function.include.php require
: http://us2.php.net/manual/en/function.require.php shell_exec
: http://us2.php.net/manual/en/function.shell-exec.php curl_init
: http://us2.php.net/manual/en/function.curl-init.php curl_setopt
: http://us2.php.net/manual/en/function.curl-setopt.php curl_exec
: http://us2.php.net/manual/en/function.curl-exec.php curl_close
: http://us2.php.net/manual/en/function.curl-close.php you can use the backtick notation:
`php file.php`;
You can also put this at the top of the php file to indicate the interpreter:
#!/usr/bin/php
Change it to where you put php. Then give execute permission on the file and you can call the file without specifying php:
`./file.php`
If you want to capture the output of the script:
$output = `./file.php`; echo $output;
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