Exec a shell command in Go

Question

I'm looking to execute a shell command in Go and get the resulting output as a string in my program. I saw the Rosetta Code version:

package main import "fmt" import "exec"  func main() {   cmd, err := exec.Run("/bin/ls", []string{"/bin/ls"}, []string{}, "", exec.DevNull, exec.PassThrough, exec.PassThrough)   if (err != nil) {     fmt.Println(err)     return   }   cmd.Close() 

But this doesn't capture the actual standard out or err in a way that I can programatically access - those still print out to the regular stdout / stderr. I saw that using Pipe as the out or err could help elsewhere, but no example of how to do so. Any ideas?

Answer 1

The package "exec" was changed a little bit. The following code worked for me.

package main  import (     "fmt"     "os/exec" )  func main() {     app := "echo"      arg0 := "-e"     arg1 := "Hello world"     arg2 := "\n\tfrom"     arg3 := "golang"      cmd := exec.Command(app, arg0, arg1, arg2, arg3)     stdout, err := cmd.Output()      if err != nil {         fmt.Println(err.Error())         return     }      // Print the output     fmt.Println(string(stdout)) } 

I hope this helps!