Exclude Tags Based on Content in Beautifulsoup

Question

I'm scraping html data that is similar to the following:

<div class="target-content">
    <p id="random1">
      "the content of the p"
    </p>

    <p id="random2">
      "the content of the p"
    </p>

    <p>
      <q class="semi-predictable">
         "q tag content that I don't want
      </q>
    </p>

    <p id="random3">
      "the content of the p"
    </p>

</div>

My goal is to get all the <p> tags, along with their content—while being able to exclude the <q> tag, along with it's content. Currently, I getting all the <p> tags with the following approach:

contentlist = soup.find('div', class_='target-content').find_all('p')

My question, is after I find the result set of all the <p> tags, how can I filter out the single <p>, along with it's content, that contains the <q>?

Of Note: after getting the results set from soup.find('div', class_='target-content')find_all('p'), I am iteratively adding each <p> from the result set to a list in the following manner:

content = ''
    for p in contentlist:
        content += str(p)

Answer 1

You can just skip p tags having the q tag inside:

for p in soup.select('div.target-content > p'):
    if p.q:  # if q is present - skip
        continue
    print(p)

where p.q is a shortcut to p.find("q"). div.target-content > p is a CSS selector which would match all p tags that are direct children of div element with target-content class.