Exclude hidden files from scandir

Question

I am using the following code to get a list of images in a directory:

$files = scandir($imagepath);

but $files also includes hidden files. How can I exclude them?

Answer 1

On Unix, you can use preg_grep to filter out filenames that start with a dot:

$files = preg_grep('/^([^.])/', scandir($imagepath));

Answer 2

I tend to use DirectoryIterator for things like this which provides a simple method for ignoring dot files:

$path = '/your/path';
foreach (new DirectoryIterator($path) as $fileInfo) {
    if($fileInfo->isDot()) continue;
    $file =  $path.$fileInfo->getFilename();
}

Answer 3

$files = array_diff(scandir($imagepath), array('..', '.'));

or

$files = array_slice(scandir($imagepath), 2);

might be faster than

$files = preg_grep('/^([^.])/', scandir($imagepath));