I have following dataframe:
A B C
Index
2001-06-30 100 2001-08-31 (=value of A at date B)
2001-07-31 200 2001-09-30 ...
2001-08-31 300 2001-10-31 ...
2001-09-30 400 2001-11-30 ...
Column B
consists of dates from column A
shifted forward by some. I would like to generate column C
that consists of the values from column A
on date B
. (preferably in the logic the Excel VLOOKUP formula would do it. I am not looking for simply shift(-2)
here because in reality the shift between B
and Index
is not always equal).
I tried df.loc['B', 'A']
but this most probably too simplistic and produced an error.
I think you need map
by column A
:
df['C'] = df.B.map(df.A)
print (df)
A B C
Index
2001-06-30 100 2001-08-31 300.0
2001-07-31 200 2001-09-30 400.0
2001-08-31 300 2001-10-31 NaN
2001-09-30 400 2001-11-30 NaN
It is same as:
df['C'] = df.B.map(df.A.to_dict())
print (df)
A B C
Index
2001-06-30 100 2001-08-31 300.0
2001-07-31 200 2001-09-30 400.0
2001-08-31 300 2001-10-31 NaN
2001-09-30 400 2001-11-30 NaN
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With