Excel SUMIFS equivalent in R

Question

I'm very very new to R and am looking at ways of recreating an Excel VBA macro and Excel worksheet functions such as SUMIFS. SUMIFS sums a column if the row has entries matching multiple conditions on its other columns.

I have the below data frame and I want to compute a new column. The new column is the sum of Sample for all rows that overlap with the Start Date and EndDate range. For example on line 1 it would be 697 (the sum of the first 3 lines). The criteria for the sum specifically: include Sample if EndDate >= StartDate[i] & StartDate <=EndDate[i]

 StartDate   EndDate    Sample  *SUMIFS example*
 10/01/14   24/01/14    139         *697*
 12/01/14   26/01/14    136 
 19/01/14   02/02/14    422 
 25/01/14   08/02/14    762 
 29/01/14   12/02/14    899 
 05/02/14   19/02/14    850 
 07/02/14   21/02/14    602 
 09/02/14   23/02/14    180 
 18/02/14   04/03/14    866 

Any comments or pointers would be greatly appreciated.

Answer 1

You could do this with a loop or with a Cartesian merge. I don't know of any built in functions to do exactly this.

library(dplyr)

x = structure(list(StartDate = structure(c(1389312000, 1389484800, 
1390089600, 1390608000, 1390953600, 1391558400, 1391731200, 1391904000, 
1392681600), tzone = "UTC", class = c("POSIXct", "POSIXt")), 
    EndDate = structure(c(1390521600, 1390694400, 1391299200, 
    1391817600, 1392163200, 1392768000, 1392940800, 1393113600, 
    1393891200), tzone = "UTC", class = c("POSIXct", "POSIXt"
    )), Sample = c(139L, 136L, 422L, 762L, 899L, 850L, 602L, 
    180L, 866L)), .Names = c("StartDate", "EndDate", "Sample"
), row.names = c(NA, -9L), class = "data.frame")

x2 = x
names(x2)=c('StartDate2','EndDate2','Sample2')
x3 = merge(x,x2,allow.cartesian =T)
x4 = summarise(group_by(x3,StartDate,EndDate),
    sumifs=sum(Sample2[EndDate2 >= StartDate & StartDate2 <= EndDate]))
x_sumifs = merge(x,x4,by=c('StartDate','EndDate'))

This is what the output looks like.

> x_sumifs
   StartDate    EndDate Sample sumifs
1 2014-01-10 2014-01-24    139    697
2 2014-01-12 2014-01-26    136   1459
3 2014-01-19 2014-02-02    422   2358
4 2014-01-25 2014-02-08    762   3671
5 2014-01-29 2014-02-12    899   3715
6 2014-02-05 2014-02-19    850   4159
7 2014-02-07 2014-02-21    602   4159
8 2014-02-09 2014-02-23    180   3397
9 2014-02-18 2014-03-04    866   2498

Answer 2

You could use lapply/sapply from base R to do this. x from @cameron.bracken's post.

x$sumifs <- sapply(seq_len(nrow(x)), function(i) with(x, 
             sum(Sample[EndDate >= StartDate[i] & StartDate <= EndDate[i]])))

x
#   StartDate    EndDate Sample sumifs
#1 2014-01-10 2014-01-24    139    697
#2 2014-01-12 2014-01-26    136   1459
#3 2014-01-19 2014-02-02    422   2358
#4 2014-01-25 2014-02-08    762   3671
#5 2014-01-29 2014-02-12    899   3715
#6 2014-02-05 2014-02-19    850   4159
#7 2014-02-07 2014-02-21    602   4159
#8 2014-02-09 2014-02-23    180   3397
#9 2014-02-18 2014-03-04    866   2498