exact way how final methods works in java

Question

class Clidder {
    private final void flipper() {
        System.out.println("Clidder");
    }
}
public class Clidlet extends Clidder {
    public final void flipper() {
        System.out.println("Clidlet");
    }
    public static void main(String args[]) {
        new Clidlet().flipper();
    }
}

what is the result? to this question I expected the answer "compilation fails" because final method cannot be overridden and it does not allow inheritance. but the answer was "Cliddet" why is that? did I misunderstand something in this concept. how can this be the output? please explain.

Answer 1

The private modifier indicates that the method of flipper() in class of Clidder can not be seen from child class Clidlet. So it is not overriding but just looks like a new method declaration in the child class. Private method/field can not be override because it can not be seen.