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I have a regex which has optional anchors at the end e.g.
(\.|,|\/) I am trying to add ")" to this but if I escape it
(/.|,|\/|\)) it isn't found and if don't escape it is treated as part of the expression and fails since there is no open parens. How can I escape it so it is treated as a character and found?
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Since parentheses are also used for capturing and non-capturing groups, we have to escape the opening parenthesis with a backslash. An explanation of how literalRegex works: / — Opens or begins regex. \( — Escapes a single opening parenthesis literal.
The backslash in a regular expression precedes a literal character. You also escape certain letters that represent common character classes, such as \w for a word character or \s for a space.
By placing part of a regular expression inside round brackets or parentheses, you can group that part of the regular expression together. This allows you to apply a quantifier to the entire group or to restrict alternation to part of the regex. Only parentheses can be used for grouping.
This answer is not useful. Show activity on this post. [] denotes a character class. () denotes a capturing group. [a-z0-9] -- One character that is in the range of a-z OR 0-9.
\) is the correct way for escaping a paranthesis. Make sure you are properly escaping the \(\\) in the string literal.
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