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Why doesn't this work?
$drvrInstFilePath = "$sharePath\$imageName\ISO`$OEM$`$1\RPKTools\RPKDriverInst.bat" echo $drvrInstFilePath $drvrInstContent = Get-Content -LiteralPath "$sharePath\$imageName\ISO`$OEM$`$1\RPKTools\RPKDriverInst.bat" | Out-String The echo shows the right path, but the Get-Content command expands the $oem and $1 to blank strings, even though they are escaped. Why?
930
$? Contains the execution status of the last command. It contains True if the last command succeeded and False if it failed. For cmdlets and advanced functions that are run at multiple stages in a pipeline, for example in both process and end blocks, calling this.
The $_ is a variable or also referred to as an operator in PowerShell that is used to retrieve only specific values from the field. It is piped with various cmdlets and used in the “Where” , “Where-Object“, and “ForEach-Object” clauses of the PowerShell.
Can you give us a bit more details about your code? (To escape the backslash you need to use double backslash : "\\" instead of "\".)
Instead of messing around with escaping dollar signs, use single quotes ' instead of double quotes ". It prevents PowerShell expanding $ into a variable. Like so,
$p = "C:\temp\Share\ISO$OEM$" # Output C:\temp\Share\ISO$ $p = 'C:\temp\Share\ISO$OEM$' # Output C:\temp\Share\ISO$OEM$ If you need to create a path by using variables, consider using Join-Path. Like so,
$s = "Share" join-path "C:\temp\$s" '\ISO$OEM$' # Output C:\temp\Share\ISO$OEM$ You can actually just use a tick mark to escape the $ like so:
`$ Example:
$number = 5 Write-Host "`$${number}" # Output: $5 If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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